Mutable, Immutable in Python3

Python can be either mutable or immutable.

Lets dive deeper into the details of it… Since everything in Python is an Object, every variable holds an object instance. When an object is initiated, it is assigned a unique object id. Its type is defined at runtime and once set can never change, however its state can be changed if it is mutable. Simple put, a mutable object can be changed after it is created, and an immutable object can’t.

Objects of built-in types like (int, float, bool, str, tuple, unicode) are immutable. Objects of built-in types like (list, set, dict) are mutable. Custom classes are generally mutable. To simulate immutability in a class, one should override attribute setting and deletion to raise exceptions.

ID and TYPE

The built-in function id() returns the identity of an object as an integer. This integer usually corresponds to the object’s location in memory, although this is specific to the Python implementation and the platform being used. The is operator compares the identity of two objects.

The built-in function type() returns the type of an object.

Example

''' Example 1 '''
>>> x = "Holberton"
>>> y = "Holberton"
>>> id(x)
140135852055856
>>> id(y)
140135852055856
>>> print(x is y) '''comparing the types'''
True''' Example 2 '''
>>> a = 50
>>> type(a)
<class: ‘int’>
>>> b = "Holberton"
>>> type(b)
<class: 'string'>

Mutable and Immutable Objects

So as we discussed earlier, a mutable object can change its state or contents and immutable objects cannot.

Mutable objects:
list, dict, set, byte array
Immutable objects:
int, float, complex, string, tuple,
frozen set [note: immutable version of set], 
bytes

A practical example to find out the mutability of object types

x = 10
x = y

We are creating an object of type int. identifiers x and y points to the same object.

id(x) == id(y)
id(y) == id(10)

if we do a simple operation.

x = x + 1

Now

id(x) != id(y)
id(x) != id(10)

The object in which x was tagged is changed. object 10 was never modified. Immutable objects doesn’t allow modification after creation

In the case of mutable objects

m = list([1, 2, 3])
n = m

We are creating an object of type list. identifiers m and m tagged to the same list object, which is a collection of 3 immutable int objects.

m = list([1, 2, 3])
n = m

We are creating an object of type list. identifiers m and m tagged to the same list object, which is a collection of 3 immutable int objects.

id(m) == id(n)

Now poping an item from list object does change the object,

m.pop()

object id will not be changed

id(m) == id(n)

Exceptions in immutability..

Not all of the immutable objects are actually immutable. Confused? Let me explain.

As discussed earlier, Python containers liked tuples are immutable. That means value of a tuple can't be changed after it is created. But the "value" of a tuple is infact a sequence of names with unchangeable bindings to objects. The key thing to note is that the bindings are unchangeable, not the objects they are bound to.

tuple t = (‘holberton’, [1, 2, 3])

The above tuple t contains elements of different data types, the first one is an immutable string and the second one is a mutable list.The tuple itself isn’t mutable . i.e. it doesn’t have any methods for changing its contents. Likewise, the string is immutable because strings don’t have any mutating methods. But the list object does have mutating methods, so it can be changed. This is a subtle point, but nonetheless important: the “value” of an immutable object can’t change, but it’s constituent objects can.

How objects are passed to Functions

Its important for us to know difference between mutable and immutable types and how they are treated when passed onto functions .Memory efficiency is highly affected when the proper objects are used.

For example if a mutable object is called by reference in a function, it can change the original variable itself. Hence to avoid this, the original variable needs to be copied to another variable. Immutable objects can be called by reference because its value cannot be changed anyways.

def updateList(list1):
    list1 += [10]n = [5, 6]
print(id(n))                  # 140312184155336updateList(n)
print(n)                      # [5, 6, 10]
print(id(n))                  # 140312184155336

As we can see from the above example, we have called the list via call by reference, so the changes are made to the original list itself.

Example:

def updateNumber(n):
    print(id(n))
    n += 10b = 5
print(id(b))                   # 10055680
updateNumber(b)                # 10055680
print(b)                       # 5

In the above example the same object is passed to the function, but the variables value doesn’t change even though the object is identical. This is called pass by value. When the value is called by the function, only the value of the variable is passed, not the object itself. So the variable referencing the object is not changed, but the object itself is being changed but within the function scope only. The change is not reflected.